2x^2-28=10x

Solution for 2x^2-28=10x equation:

2x^2-28=10x

We move all terms to the left:

2x^2-28-(10x)=0

a = 2; b = -10; c = -28;
Δ = b2-4ac
Δ = -102-4·2·(-28)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-18}{2*2}=\frac{-8}{4}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+18}{2*2}=\frac{28}{4}
=7
$